Integrand size = 14, antiderivative size = 54 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\frac {2 \sqrt {c+d x} \cosh \left (a+b \sqrt {c+d x}\right )}{b d}-\frac {2 \sinh \left (a+b \sqrt {c+d x}\right )}{b^2 d} \]
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Time = 0.04 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {5418, 5412, 3377, 2717} \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\frac {2 \sqrt {c+d x} \cosh \left (a+b \sqrt {c+d x}\right )}{b d}-\frac {2 \sinh \left (a+b \sqrt {c+d x}\right )}{b^2 d} \]
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Rule 2717
Rule 3377
Rule 5412
Rule 5418
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \sinh \left (a+b \sqrt {x}\right ) \, dx,x,c+d x\right )}{d} \\ & = \frac {2 \text {Subst}\left (\int x \sinh (a+b x) \, dx,x,\sqrt {c+d x}\right )}{d} \\ & = \frac {2 \sqrt {c+d x} \cosh \left (a+b \sqrt {c+d x}\right )}{b d}-\frac {2 \text {Subst}\left (\int \cosh (a+b x) \, dx,x,\sqrt {c+d x}\right )}{b d} \\ & = \frac {2 \sqrt {c+d x} \cosh \left (a+b \sqrt {c+d x}\right )}{b d}-\frac {2 \sinh \left (a+b \sqrt {c+d x}\right )}{b^2 d} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.93 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\frac {2 \left (b \sqrt {c+d x} \cosh \left (a+b \sqrt {c+d x}\right )-\sinh \left (a+b \sqrt {c+d x}\right )\right )}{b^2 d} \]
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Time = 1.31 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.17
method | result | size |
derivativedivides | \(\frac {2 \left (a +b \sqrt {d x +c}\right ) \cosh \left (a +b \sqrt {d x +c}\right )-2 \sinh \left (a +b \sqrt {d x +c}\right )-2 a \cosh \left (a +b \sqrt {d x +c}\right )}{b^{2} d}\) | \(63\) |
default | \(\frac {2 \left (a +b \sqrt {d x +c}\right ) \cosh \left (a +b \sqrt {d x +c}\right )-2 \sinh \left (a +b \sqrt {d x +c}\right )-2 a \cosh \left (a +b \sqrt {d x +c}\right )}{b^{2} d}\) | \(63\) |
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none
Time = 0.26 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.81 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\frac {2 \, {\left (\sqrt {d x + c} b \cosh \left (\sqrt {d x + c} b + a\right ) - \sinh \left (\sqrt {d x + c} b + a\right )\right )}}{b^{2} d} \]
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Time = 0.20 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.20 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\begin {cases} x \sinh {\left (a \right )} & \text {for}\: b = 0 \wedge \left (b = 0 \vee d = 0\right ) \\x \sinh {\left (a + b \sqrt {c} \right )} & \text {for}\: d = 0 \\\frac {2 \sqrt {c + d x} \cosh {\left (a + b \sqrt {c + d x} \right )}}{b d} - \frac {2 \sinh {\left (a + b \sqrt {c + d x} \right )}}{b^{2} d} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 111 vs. \(2 (48) = 96\).
Time = 0.20 (sec) , antiderivative size = 111, normalized size of antiderivative = 2.06 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=-\frac {b {\left (\frac {{\left ({\left (d x + c\right )} b^{2} e^{a} - 2 \, \sqrt {d x + c} b e^{a} + 2 \, e^{a}\right )} e^{\left (\sqrt {d x + c} b\right )}}{b^{3}} - \frac {{\left ({\left (d x + c\right )} b^{2} + 2 \, \sqrt {d x + c} b + 2\right )} e^{\left (-\sqrt {d x + c} b - a\right )}}{b^{3}}\right )} - 2 \, {\left (d x + c\right )} \sinh \left (\sqrt {d x + c} b + a\right )}{2 \, d} \]
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none
Time = 0.28 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.19 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=\frac {{\left (\sqrt {d x + c} b - 1\right )} e^{\left (\sqrt {d x + c} b + a\right )}}{b^{2} d} + \frac {{\left (\sqrt {d x + c} b + 1\right )} e^{\left (-\sqrt {d x + c} b - a\right )}}{b^{2} d} \]
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Time = 1.19 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.80 \[ \int \sinh \left (a+b \sqrt {c+d x}\right ) \, dx=-\frac {2\,\left (\mathrm {sinh}\left (a+b\,\sqrt {c+d\,x}\right )-b\,\mathrm {cosh}\left (a+b\,\sqrt {c+d\,x}\right )\,\sqrt {c+d\,x}\right )}{b^2\,d} \]
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